Sarà Viktorija Golubic (WTA 54) la seconda singolarista al fianco di Timea Bacsinszky (22) per la semifinale di Fed Cup in programma nel weekend a Minsk. Sarà proprio la zurighese ad aprire le danze nella sfida con la Bielorussia, affrontando sabato alle 12h00 la numero 1 delle padrone di casa, Aliaksandra Sasnovich (96). Le due si sono affrontate appena qualche giorno fa a Bienne, e il successo era andato nettamente alla ragazza dell'Est.
Il capitano Heinz Günthardt ha dunque deciso di seguire i valori della classifica, tenendo come riserva Belinda Bencic (129), che dovrebbe giocare domenica il doppio in coppia con Martina Hingis. Nel secondo confronto della prima giornata, Bacsinszky sfiderà Aryna Sabalenka (125).
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