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Stan Wawrinka (ATP 3) si è imposto con il punteggio di 6-3 6-4 contro Paolo Lorenzi (35) nella sua entrata in materia al torneo di Indian Wells. Il vodese ha chiuso il match a suo favore dopo 7 punti consecutivi conquistati, inclusi due ace. Nei sedicesimi l'elvetico affronterà il tedesco Philipp Kohlschreiber (31), contro il quale il bilancio degli scontri diretti è nettamente a favore (4-0 per Wawrinka).
Una settimana dopo la sconfitta al primo turno di Dubai, dove era opposto al bosniaco Damir Dzumhur (67), il rossocrociato ha dovuto impegnarsi per battere l'italiano. Si trattava infatti soltanto del suo secondo match disputato nelle ultime otto settimane. Il bilancio di Wawrinka al termine del match parla di una mancanza di efficacia da correggere in vista dei prossimi impegni. Contro Lorenzi l'esempio viene dal secondo set, quando ha dovuto attendere la nona palla break per riuscire a strappare il servizio al suo avversario.
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