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Stanislas Wawrinka (ATP 8) si è qualificato per i quarti di finale degli Australian Open superando lo spagnolo Tommy Robredo (18), già giustiziere di Roger Federer agli US Open 2013, per 6-3 7-6 (7/3) 7-6 (7/5). Il vodese ha offerto una prestazione solida e convincente. Dopo aver dominato il primo set, le ultime due frazioni sono state combattute: Stan ha dovuto infatti giocarsi i punti decisivi al tie-break, mantenendo comunque la lucidità per uscirne da vincitore.
Ad attendere il 28enne di St.Barthélemy ci sarà Novak Djokovic (2), che ha superato l'ostacolo Fabio Fognini (16) con un perentorio 6-3 6-0 6-2. Lo scorso anno sempre a Melbourne l'incontro tra lo svizzero e il serbo finì con con la vittoria di "Djoker" dopo una maratona di cinque set, in uno dei match più belli della passata stagione.
Gallery audio - Wawrinka batte Robredo e attende Nole
Contenuto audio
Il servizio di Ivan Zippilli
RSI Sport 19.01.2014, 19:21
Le dichiarazioni di Stanislas Wawrinka
RSI Sport 19.01.2014, 23:19
Gallery video - Wawrinka batte Robredo e attende Nole
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